Optimal. Leaf size=126 \[ -4 a^3 x-\frac {4 a^3 \cot (c+d x)}{d}+\frac {2 i a^3 \cot ^2(c+d x)}{d}+\frac {4 a^3 \cot ^3(c+d x)}{3 d}-\frac {11 i a^3 \cot ^4(c+d x)}{20 d}+\frac {4 i a^3 \log (\sin (c+d x))}{d}-\frac {\cot ^5(c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{5 d} \]
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Rubi [A]
time = 0.15, antiderivative size = 126, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {3634, 3672,
3610, 3612, 3556} \begin {gather*} -\frac {11 i a^3 \cot ^4(c+d x)}{20 d}+\frac {4 a^3 \cot ^3(c+d x)}{3 d}+\frac {2 i a^3 \cot ^2(c+d x)}{d}-\frac {4 a^3 \cot (c+d x)}{d}+\frac {4 i a^3 \log (\sin (c+d x))}{d}-\frac {\cot ^5(c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{5 d}-4 a^3 x \end {gather*}
Antiderivative was successfully verified.
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Rule 3556
Rule 3610
Rule 3612
Rule 3634
Rule 3672
Rubi steps
\begin {align*} \int \cot ^6(c+d x) (a+i a \tan (c+d x))^3 \, dx &=-\frac {\cot ^5(c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{5 d}-\frac {1}{5} \int \cot ^5(c+d x) (a+i a \tan (c+d x)) \left (-11 i a^2+9 a^2 \tan (c+d x)\right ) \, dx\\ &=-\frac {11 i a^3 \cot ^4(c+d x)}{20 d}-\frac {\cot ^5(c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{5 d}-\frac {1}{5} \int \cot ^4(c+d x) \left (20 a^3+20 i a^3 \tan (c+d x)\right ) \, dx\\ &=\frac {4 a^3 \cot ^3(c+d x)}{3 d}-\frac {11 i a^3 \cot ^4(c+d x)}{20 d}-\frac {\cot ^5(c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{5 d}-\frac {1}{5} \int \cot ^3(c+d x) \left (20 i a^3-20 a^3 \tan (c+d x)\right ) \, dx\\ &=\frac {2 i a^3 \cot ^2(c+d x)}{d}+\frac {4 a^3 \cot ^3(c+d x)}{3 d}-\frac {11 i a^3 \cot ^4(c+d x)}{20 d}-\frac {\cot ^5(c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{5 d}-\frac {1}{5} \int \cot ^2(c+d x) \left (-20 a^3-20 i a^3 \tan (c+d x)\right ) \, dx\\ &=-\frac {4 a^3 \cot (c+d x)}{d}+\frac {2 i a^3 \cot ^2(c+d x)}{d}+\frac {4 a^3 \cot ^3(c+d x)}{3 d}-\frac {11 i a^3 \cot ^4(c+d x)}{20 d}-\frac {\cot ^5(c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{5 d}-\frac {1}{5} \int \cot (c+d x) \left (-20 i a^3+20 a^3 \tan (c+d x)\right ) \, dx\\ &=-4 a^3 x-\frac {4 a^3 \cot (c+d x)}{d}+\frac {2 i a^3 \cot ^2(c+d x)}{d}+\frac {4 a^3 \cot ^3(c+d x)}{3 d}-\frac {11 i a^3 \cot ^4(c+d x)}{20 d}-\frac {\cot ^5(c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{5 d}+\left (4 i a^3\right ) \int \cot (c+d x) \, dx\\ &=-4 a^3 x-\frac {4 a^3 \cot (c+d x)}{d}+\frac {2 i a^3 \cot ^2(c+d x)}{d}+\frac {4 a^3 \cot ^3(c+d x)}{3 d}-\frac {11 i a^3 \cot ^4(c+d x)}{20 d}+\frac {4 i a^3 \log (\sin (c+d x))}{d}-\frac {\cot ^5(c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{5 d}\\ \end {align*}
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Mathematica [B] Both result and optimal contain complex but leaf count is larger than twice
the leaf count of optimal. \(359\) vs. \(2(126)=252\).
time = 1.65, size = 359, normalized size = 2.85 \begin {gather*} \frac {a^3 \csc (c) \csc ^5(c+d x) (\cos (3 d x)+i \sin (3 d x)) \left (-225 i \cos (2 c+d x)+600 d x \cos (2 c+d x)-105 i \cos (2 c+3 d x)+300 d x \cos (2 c+3 d x)+105 i \cos (4 c+3 d x)-300 d x \cos (4 c+3 d x)-60 d x \cos (4 c+5 d x)+60 d x \cos (6 c+5 d x)-75 \cos (d x) \left (-3 i+8 d x-2 i \log \left (\sin ^2(c+d x)\right )\right )-150 i \cos (2 c+d x) \log \left (\sin ^2(c+d x)\right )-75 i \cos (2 c+3 d x) \log \left (\sin ^2(c+d x)\right )+75 i \cos (4 c+3 d x) \log \left (\sin ^2(c+d x)\right )+15 i \cos (4 c+5 d x) \log \left (\sin ^2(c+d x)\right )-15 i \cos (6 c+5 d x) \log \left (\sin ^2(c+d x)\right )+470 \sin (d x)+960 \text {ArcTan}(\tan (4 c+d x)) \sin (c) \sin ^5(c+d x)+360 \sin (2 c+d x)-280 \sin (2 c+3 d x)-135 \sin (4 c+3 d x)+83 \sin (4 c+5 d x)\right )}{240 d (\cos (d x)+i \sin (d x))^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.20, size = 132, normalized size = 1.05
method | result | size |
risch | \(\frac {8 a^{3} c}{d}-\frac {2 i a^{3} \left (240 \,{\mathrm e}^{8 i \left (d x +c \right )}-585 \,{\mathrm e}^{6 i \left (d x +c \right )}+695 \,{\mathrm e}^{4 i \left (d x +c \right )}-385 \,{\mathrm e}^{2 i \left (d x +c \right )}+83\right )}{15 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{5}}+\frac {4 i a^{3} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}\) | \(100\) |
derivativedivides | \(\frac {-i a^{3} \left (-\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}-\ln \left (\sin \left (d x +c \right )\right )\right )-3 a^{3} \left (-\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}+\cot \left (d x +c \right )+d x +c \right )+3 i a^{3} \left (-\frac {\left (\cot ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )+a^{3} \left (-\frac {\left (\cot ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}-\cot \left (d x +c \right )-d x -c \right )}{d}\) | \(132\) |
default | \(\frac {-i a^{3} \left (-\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}-\ln \left (\sin \left (d x +c \right )\right )\right )-3 a^{3} \left (-\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}+\cot \left (d x +c \right )+d x +c \right )+3 i a^{3} \left (-\frac {\left (\cot ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )+a^{3} \left (-\frac {\left (\cot ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}-\cot \left (d x +c \right )-d x -c \right )}{d}\) | \(132\) |
norman | \(\frac {-\frac {a^{3}}{5 d}-4 a^{3} x \left (\tan ^{5}\left (d x +c \right )\right )+\frac {4 a^{3} \left (\tan ^{2}\left (d x +c \right )\right )}{3 d}-\frac {4 a^{3} \left (\tan ^{4}\left (d x +c \right )\right )}{d}-\frac {3 i a^{3} \tan \left (d x +c \right )}{4 d}+\frac {2 i a^{3} \left (\tan ^{3}\left (d x +c \right )\right )}{d}}{\tan \left (d x +c \right )^{5}}+\frac {4 i a^{3} \ln \left (\tan \left (d x +c \right )\right )}{d}-\frac {2 i a^{3} \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{d}\) | \(134\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.59, size = 109, normalized size = 0.87 \begin {gather*} -\frac {240 \, {\left (d x + c\right )} a^{3} + 120 i \, a^{3} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) - 240 i \, a^{3} \log \left (\tan \left (d x + c\right )\right ) + \frac {240 \, a^{3} \tan \left (d x + c\right )^{4} - 120 i \, a^{3} \tan \left (d x + c\right )^{3} - 80 \, a^{3} \tan \left (d x + c\right )^{2} + 45 i \, a^{3} \tan \left (d x + c\right ) + 12 \, a^{3}}{\tan \left (d x + c\right )^{5}}}{60 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.44, size = 219, normalized size = 1.74 \begin {gather*} -\frac {2 \, {\left (240 i \, a^{3} e^{\left (8 i \, d x + 8 i \, c\right )} - 585 i \, a^{3} e^{\left (6 i \, d x + 6 i \, c\right )} + 695 i \, a^{3} e^{\left (4 i \, d x + 4 i \, c\right )} - 385 i \, a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} + 83 i \, a^{3} + 30 \, {\left (-i \, a^{3} e^{\left (10 i \, d x + 10 i \, c\right )} + 5 i \, a^{3} e^{\left (8 i \, d x + 8 i \, c\right )} - 10 i \, a^{3} e^{\left (6 i \, d x + 6 i \, c\right )} + 10 i \, a^{3} e^{\left (4 i \, d x + 4 i \, c\right )} - 5 i \, a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} + i \, a^{3}\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} - 1\right )\right )}}{15 \, {\left (d e^{\left (10 i \, d x + 10 i \, c\right )} - 5 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 10 \, d e^{\left (6 i \, d x + 6 i \, c\right )} - 10 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 5 \, d e^{\left (2 i \, d x + 2 i \, c\right )} - d\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.36, size = 218, normalized size = 1.73 \begin {gather*} \frac {4 i a^{3} \log {\left (e^{2 i d x} - e^{- 2 i c} \right )}}{d} + \frac {- 480 i a^{3} e^{8 i c} e^{8 i d x} + 1170 i a^{3} e^{6 i c} e^{6 i d x} - 1390 i a^{3} e^{4 i c} e^{4 i d x} + 770 i a^{3} e^{2 i c} e^{2 i d x} - 166 i a^{3}}{15 d e^{10 i c} e^{10 i d x} - 75 d e^{8 i c} e^{8 i d x} + 150 d e^{6 i c} e^{6 i d x} - 150 d e^{4 i c} e^{4 i d x} + 75 d e^{2 i c} e^{2 i d x} - 15 d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 1.61, size = 212, normalized size = 1.68 \begin {gather*} \frac {6 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 45 i \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 190 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 660 i \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 7680 i \, a^{3} \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + i\right ) + 3840 i \, a^{3} \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 2460 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + \frac {-8768 i \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 2460 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 660 i \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 190 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 45 i \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 6 \, a^{3}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5}}}{960 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 4.11, size = 92, normalized size = 0.73 \begin {gather*} -\frac {8\,a^3\,\mathrm {atan}\left (2\,\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )}{d}-\frac {4\,a^3\,{\mathrm {tan}\left (c+d\,x\right )}^4-a^3\,{\mathrm {tan}\left (c+d\,x\right )}^3\,2{}\mathrm {i}-\frac {4\,a^3\,{\mathrm {tan}\left (c+d\,x\right )}^2}{3}+\frac {a^3\,\mathrm {tan}\left (c+d\,x\right )\,3{}\mathrm {i}}{4}+\frac {a^3}{5}}{d\,{\mathrm {tan}\left (c+d\,x\right )}^5} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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